Regular expression pattern in Java always is the best method to validate an user’s phone number. Here i provide a regex pattern to determines if the phone number is in correct format, the pattern force starting with 3 digits follow by a “-” and 7 digits at the end.
\\d{3}-\\d{7}
Explanation
\\d = only digit allow
{3} = length
All phone numbers must in “xxx-xxxxxxx” format. For example
1) 012-6677889 – Passed
2) 01216677889 – Failed , “-” missing
3) A12-6677889 – Failed , only digit allow
4) 012-66778899 – Failed, only 7 digits at the end
Full source code of phone number validation in Java
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class ValidatePhoneNumber {
public static void main(String[] argv) {
String sPhoneNumber = "605-8889999";
//String sPhoneNumber = "605-88899991";
//String sPhoneNumber = "605-888999A";
Pattern pattern = Pattern.compile("\\d{3}-\\d{7}");
Matcher matcher = pattern.matcher(sPhoneNumber);
if (matcher.matches()) {
System.out.println("Phone Number Valid");
}
else
{
System.out.println("Phone Number must be in the form XXX-XXXXXXX");
}
}
}
I want phone number starts with 7,8,9
can u say regex for it
How should i ask user to enter only 60
08 123 1234
(408) 123-1234
408-123-1234
its not working validation pls help me
HOW DO I CHECK FOR A NPA OR NXX NUMBER ?
That’s pretty restrictive. I am looking for a way to allow phone number like:
1 408 123 1234
1(408) 123-1234 and combinations thereof e.g. 1(408) 123 1234, 1 (408)-123-1234…
1-408-123-1234 and combinations thereof
Simplest way I can think of is
a) Remove all spaces
b) Remove all dashes
c) Remove all parentheses
What is left should consist only of numbers. Anything else would result in a validation error.
Struggled all day and night trying to figure out a solution for a college project. Thanks for the pointers.
Thank a lot
Nice example
Pls give me some idea 2 write telephone line checking code in java
I’m new to springs can someone help me validate a contact number in Spring .
Thanks.
hi i want to know how should be the pattern if i want the user to enter a number begining with 21 or 27 followed by 6 numbers
please help me
Thanks
Pattern pattern = Pattern.compile(“^(21)-\d{7}”);
Matcher matcher = pattern.matcher(sPhoneNumber);
Unfortunately this works for US based numbers only. Not everyone in the world has the same style phone number.
Try understand the concept, and you can customize it to any use case.
Hi Sir,
I am trying to validate US phone number in the form of 555-555-5555 and its working fine and if this is not matching its giving error message is fine.
But, its failing when I submit the form if the area code of US is not matching. I need to validate area code also before form submit. Can you please help me on this. Error am getting for reference “Phone number (US)324-765-4567 is not valid: Number 324-765-4567 belongs to a non valid area code”. Here 324 is not the area code of US.
I created a phone number pattern a little different. I’m trying to verify it’s validity. ^(\d?\d?\d?\d)?(\d{3})(\d{7})$
First I have a method that strips non-numbers out of the string because there are all kinds of formats people use including parenthesis dashes, periods, etc.
My regular expression matches first 7 digits. It’s in a group so I can pull it out if I want. Next I match 3 digits for the area code. Again it is grouped so that I can pull it out and use it or store it however I want it. Then I have an optional group for the country code. If I do have the group, then I have at least one digit with 3 more optional digits.
Any comments suggestions?
I’ve written some basic unit tests, but I might not be testing some edge cases.
your pattern is great, pattern contains unlimited possibilities, and just make sure you make a detail unit test to cover all your use case
hi, i want to check that no. must be of 10 digits with first digit non-zero, how to write RE for this ?