How to get user input in Java

By mkyong | Updated: April 16, 2019

Viewed: 552 (+33 pv/w)

Tags: bufferedreader java scanner user input

In Java, we can use java.util.Scanner to get user input from console.

1. Scanner

1.1 Read a line.

package com.mkyong;

import java.util.Scanner;

public class UserInputExample1 {

    public static void main(String[] args) {

		// auto close scanner
        try (Scanner scanner = new Scanner(System.in)) {

            System.out.print("Enter something : ");

            String input = scanner.nextLine();  // Read user input

            System.out.println("User Input : " + input);

        }

    }
}

Output

Enter something : hello world
User Input : hello world

1.1 Read different data type

package com.mkyong;

import java.util.Scanner;

public class UserInputExample2 {

    public static void main(String[] args) {

        try (Scanner scanner = new Scanner(System.in)) {

            System.out.println("Please enter your name : ");
            String name = scanner.next(); // get string

            System.out.println("Please enter your age : ");
            int age = scanner.nextInt(); // get integer

            System.out.println("Please enter your salary : ");
            double salary = scanner.nextDouble(); // get double

            System.out.format("Name : %s, Age : %d, Salary : %.2f", name, age, salary);
        }

    }
}

Output

Please enter your name : 
mkyong
Please enter your age : 
38
Please enter your salary : 
9000
Name : mkyong, Age : 38, Salary : 9000.00

2. InputStreamReader + BufferedReader

2.1 Alternative solution.

package com.mkyong;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class UserInputExample {

    public static void main(String[] args) throws IOException {

        try (BufferedReader br = new BufferedReader(new InputStreamReader(System.in))) {

            System.out.println("Please enter your name : ");
            String name = br.readLine();

            System.out.println("Please enter your age : ");
            int age = Integer.parseInt(br.readLine());

            System.out.println("Please enter your salary : ");
            double salary = Double.parseDouble(br.readLine());

            System.out.format("Name : %s, Age : %d, Salary : %.2f", name, age, salary);

        }

    }
}

Output

Please enter your name : 
Steve Jobs
Please enter your age : 
56
Please enter your salary : 
1.00
Name : Steve Jobs, Age : 56, Salary : 1.00

References

• Scanner JavaDocs