Java examples to check if an Array (String or Primitive type) contains a certain values, updated with Java 8 stream APIs.
1. String Arrays
1.1 Check if a String Array contains a certain value “A”.
StringArrayExample1.java
package com.mkyong.core;
import java.util.Arrays;
import java.util.List;
public class StringArrayExample1 {
public static void main(String[] args) {
String[] alphabet = new String[]{"A", "B", "C"};
// Convert String Array to List
List<String> list = Arrays.asList(alphabet);
if(list.contains("A")){
System.out.println("Hello A");
}
}
}
Output
Hello A
In Java 8, you can do this :
// Convert to stream and test it
boolean result = Arrays.stream(alphabet).anyMatch("A"::equals);
if (result) {
System.out.println("Hello A");
}
1.2 Example to check if a String Array contains multiple values :
StringArrayExample2.java
package com.mkyong.core;
import java.util.Arrays;
import java.util.List;
public class StringArrayExample2 {
public static void main(String[] args) {
String[] alphabet = new String[]{"A", "C"};
// Convert String Array to List
List<String> list = Arrays.asList(alphabet);
// A or B
if (list.contains("A") || list.contains("B")) {
System.out.println("Hello A or B");
}
// A and B
if (list.containsAll(Arrays.asList("A", "B"))) {
System.out.println("Hello A and B");
}
// A and C
if (list.containsAll(Arrays.asList("A", "C"))) {
System.out.println("Hello A and C");
}
}
}
Output
Hello A or B
Hello A and C
2. Primitive Arrays
2.1 For primitive array like int[], you need to loop it and test the condition manually :
PrimitiveArrayExample1.java
package com.mkyong.core;
import java.util.Arrays;
import java.util.List;
public class PrimitiveArrayExample1 {
public static void main(String[] args) {
int[] number = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
if(contains(number, 2)){
System.out.println("Hello 2");
}
}
public static boolean contains(final int[] array, final int v) {
boolean result = false;
for(int i : array){
if(i == v){
result = true;
break;
}
}
return result;
}
}
Output
Hello 2
2.2 With Java 8, coding is much simpler ~
ArrayExample1.java
package com.mkyong.core;
import java.util.stream.IntStream;
import java.util.stream.LongStream;
public class TestDate {
public static void main(String[] args) {
int[] number = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
//Java 8
boolean result = IntStream.of(number).anyMatch(x -> x == 4);
if (result) {
System.out.println("Hello 4");
} else {
System.out.println("Where is number 4?");
}
long[] lNumber = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
boolean result2 = LongStream.of(lNumber).anyMatch(x -> x == 10);
if (result2) {
System.out.println("Hello 10");
} else {
System.out.println("Where is number 10?");
}
}
}
Output
Hello 4
Hello 10
Note
To check if a primitive array contains multiple values, convert the array into a List and compare it like example 1.2 above.
To check if a primitive array contains multiple values, convert the array into a List and compare it like example 1.2 above.
Hi,
The link of the topic does not match the title.
Regards,
Adarsh
for 1.1 you could do
Arrays.stream(alphabet).filter(“A”::equals).findAny().ifPresent(s->System.out.println(“Hello A”));
which removes the need for the if below.
what about ?
static boolean contains(Integer[] ints, int k) { return (java.util.Arrays.binarySearch(ints, k)) >= 0; }The contains(array,value) worked like a dream for me to identify duplicate values as my random integers were being input into an array such that I was able to repeat the iteration without adding to the array limit.
Much appreciated.